Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
The number of elements initialized in nums1 and nums2 are m and n respectively. You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. Example:
Input: nums1 = [1,2,3,0,0,0], m = 3 nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
Solution
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# @param {Integer[]} nums1 # @param {Integer} m # @param {Integer[]} nums2 # @param {Integer} n # @return {Void} Do not return anything, modify nums1 in-place instead. defmerge(nums1, m, nums2, n) returnif n == 0
for f in1..nums1.size if m >= 1 && nums1[m - 1] > nums2[n - 1] nums1[nums1.size - f] = nums1[m - 1] m -= 1 elsif n >= 1 nums1[nums1.size - f] = nums2[n - 1] n -= 1 end end end